Problem Statement 
 On your previous quest you acquired a priceless "infinite sack". This wondrous piece of luggage will hold an endless number of items but there is a catch. The last item you put in is the first one that comes out. Accounting for this restriction, you plan your next journey.
You begin at location 0, your home. Element k of dests is a spaceseparated list of locations that can be reached from location k. For each listed location j, element k of trades contains a 2letter code NG. N is a character describing which item is needed to make the trip from location k to location j. G is also a character, and describes the item you will acquire by taking the trip. At least one of N or G will be '_', meaning you do not need an item, or do not acquire an item for the trip, respectively. For example, suppose element 3 of dests and trades are as given below.
dests[3] = "0 3 0 4"
trades[3] = "a_ __ _B D_"
One possible way to get from location 3 to location 0 requires item 'a' and earns you nothing. Another requires no item but you find item 'B'. The trip that returns to location 3 requires no item but also earns no item. Lastly, the trip to location 4 requires 'D', but produces nothing.
You can only take a trip that requires the next item you can pull out of your sack. Trips that require no item can always be taken. For example, to take the "a_" trip mentioned above, the next item that you pull out of your sack would have to be 'a'. This item is removed. You will return a int[] containing the locations that can be reached via 0 or more trips from location 0. It should be sorted in strictly increasing order. Since we allow 0 trips, the first element will always be 0. Your sack is initially empty, so no item can be pulled out. 

Definition 
 Class:  SackJourney  Method:  canReach  Parameters:  String[], String[]  Returns:  int[]  Method signature:  int[] canReach(String[] dests, String[] trades)  (be sure your method is public) 




Notes 
  The only transactions that can be made with your sack are the ones that correspond to trips. 

Constraints 
  dests will contain between 2 and 20 elements inclusive. 
  trades will contain the same number of elements as dests. 
  Each element of dests will contain between 0 and 50 characters inclusive. 
  Each element of trades will contain between 0 and 50 characters inclusive. 
  Each element of dests will be a singlespace separated list of integers with no extra leading zeros. 
  Each integer in dests will be between 0 and N1, where N is the number of elements in dests. 
  Each element of trades will be a singlespace separated list of 2 character sequences. Each character will be a letter ('A''Z','a''z') or an underscore ('_'). At least one of the characters in each sequence will be an underscore. 
  Each element of trades will contain the same number of 2 character sequences as the corresponding element of dests contains integers. 

Examples 
0)  
 {"1","2",""}  {"_A","A_",""} 
 Returns: {0, 1, 2 }  We can get to location 1 with 'A' in our sack. Removing this 'A', we can travel to location 2. 


1)  
 {"1","2",""}  {"_A","b_",""} 
 Returns: {0, 1 }  Unlike the first example, we cannot get to location 2 since we need a 'b'. 


2)  
 {"0 0 1","2","3","4","5",""}  {"_A _B __","B_","A_","__","C_",""} 
 Returns: {0, 1, 2, 3, 4 }  
