Problem Statement |
| The organization of an array A is computed as follows: Create an array B containing the exact same elements as A, but sorted in non-descending order. Count the number of distinct values for i such that A[i] is equal to B[i]. This value is the organization of the array A. For example, the organization of { 2, 1, 1, 3 } is 2 because the second and fourth elements are not changed after sorting.
Two elements may be swapped only if the organization of the array would increase as a result of the swap.
You will be given a int[] arrayData. Return the maximal number of the swap operations that can be performed.
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Definition |
| Class: | SwapSorter | Method: | maximizeSwaps | Parameters: | int[] | Returns: | int | Method signature: | int maximizeSwaps(int[] arrayData) | (be sure your method is public) |
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Constraints |
- | arrayData will have between 1 and 50 elements, inclusive. |
- | Each element of arrayData will be between 1 and 1000, inclusive. |
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Examples |
0) | |
| | Returns: 1 | The only possible swap is {2, 1, 1, 3} -> {1, 1, 2, 3} |
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1) | |
| | Returns: 3 | {7, 5, 3, 4} -> {3, 5, 7, 4} -> {3, 4, 7, 5} -> {3, 4, 5, 7} |
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2) | |
| | Returns: 2 | {2, 1, 4, 3} -> {1, 2, 4, 3} -> {1, 2, 3, 4} |
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3) | |
| {1, 7, 8, 12, 17, 19, 21, 23, 24, 25, 26, 27, 35} |
| Returns: 0 | The array is already sorted. |
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4) | |
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5) | |
| {2, 3, 4, 1, 7, 7, 5, 5, 8, 7, 10, 10, 10, 9, 9, 9} |
| Returns: 11 | |
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