Problem Statement |
| Split-and-merge is a one player game. The player starts out with several piles of coins. With each move, he can either merge two of the piles into a single pile, or split a single pile into two new non-empty piles. You are given a int[] startState, containing the starting configuration of the coins, and a int[] finishState, containing the target configuration. Each element of the int[]s represents the number of coins in a pile. The order of the elements do not matter. For example, {1, 2, 3} and {2, 1, 3} represent the same set of piles. Return the minimal number of moves necessary to reach the finishState from the startState. If a solution doesn't exist then return -1.
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Definition |
| Class: | SplitAndMergeGame | Method: | minMoves | Parameters: | int[], int[] | Returns: | int | Method signature: | int minMoves(int[] startState, int[] finishState) | (be sure your method is public) |
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Constraints |
- | startState will contain between 1 and 10 elements, inclusive. |
- | finishState will contain between 1 and 10 elements, inclusive. |
- | Each element of startState will be between 1 and 50, inclusive. |
- | Each element of finishState will be between 1 and 50, inclusive. |
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Examples |
0) | |
| | Returns: 1 | Merge the two piles to form a single pile of 3 coins. |
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1) | |
| | Returns: 1 | Split the pile of 4 coins into two piles of 2 coins. |
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2) | |
| {1, 2, 3, 4, 5, 6} | {7, 7, 7} |
| Returns: 3 | |
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3) | |
| | Returns: 2 | One way to do this is to split the pile of 3 coins into a pile of 2 coins and a pile with 1 coin. Then, merge the pile of 2 coins with the pile of 4 coins to form a pile of 6 coins. |
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4) | |
| | Returns: -1 | A solution doesn't exist. |
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