Problem Statement |
| You are trying to predict the outcome of a race between n runners, numbered from 0 to n - 1.You are given two int[]s, first and second. It is guaranteed that for all i, the runner numbered first[i] will always beat the runner numbered second[i]. Determine how many final orderings are possible, modulo 1,000,003. If the information is contradictionary, return 0. Runners are never tied. |
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Definition |
| Class: | RaceOrdering | Method: | countOrders | Parameters: | int, int[], int[] | Returns: | int | Method signature: | int countOrders(int n, int[] first, int[] second) | (be sure your method is public) |
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Constraints |
- | n will be between 1 and 30, inclusive. |
- | first and second will each contain between 0 and 15 elements, inclusive. |
- | first and second will contain the same number of elements. |
- | Each element of first and second will be between 0 and n - 1, inclusive. |
- | first[i] does not equal second[i] for all i between 0 and m - 1, inclusive, where m is the number of elements in first and second. |
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Examples |
0) | |
| | Returns: 3 | Contestant 1 beat contestant 2, so the valid orders are 012, 102 and 120. |
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1) | |
| | Returns: 8 | Contestant 0 beat contestants 1 and 2, but there is no information on contestant 3. The valid orderings are 3012, 3021, 0312, 0321, 0132, 0231, 0123 and 0213. |
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2) | |
| | Returns: 0 | There is no way to satisfy this cycle. |
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3) | |
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