Problem Statement |
| The king has been out to work for a long time and he wants to go back to his queen as fast as possible. The king is in city 0 and the queen is in city N. There are roads and flights connecting city i to city (i+1) for all i between 0 and N-1, inclusive.
You are given int[] roadTime whose i-th element is the time it takes to travel from city i to city (i+1) by road and int[] flightTime whose i-th element is the time it takes to travel from city i to city (i+1) by flight. However, taking a flight risks the life of the king due to the technological limitations in the kingdom. Hence the queen has asked the king to take at most K flights on his way.
Return the minimum amount of time in which the king can reach his queen.
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Definition |
| Class: | RoadOrFlightEasy | Method: | minTime | Parameters: | int, int[], int[], int | Returns: | int | Method signature: | int minTime(int N, int[] roadTime, int[] flightTime, int K) | (be sure your method is public) |
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Constraints |
- | N will be between 1 and 50, inclusive. |
- | roadTime will contain exactly N elements. |
- | flightTime will contain exactly N elements. |
- | Each element of roadTime and flightTime will be between 1 and 1000, inclusive. |
- | K will be between 0 and N, inclusive. |
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Examples |
0) | |
| | Returns: 13 | All flightTimes here are less than roadTimes. However the king can choose only 1 flight. The are two possible optimal routes. City 0-->1, 1-->2 by road and 2-->3 by flight takes time 4 + 6 + 3 = 13 units. City 0-->1 by road, 1-->2 by flight and 2-->3 by road also takes time 4 + 2 + 7 = 13 units. |
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1) | |
| | Returns: 9 | Now the king is allowed to take 2 flights. |
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2) | |
| | Returns: 6 | Choose all 3 flights since flights are faster than roads. |
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3) | |
| | Returns: 6 | flightTime can be larger than roadTime. So the King may take fewer than K flights even though he is allowed to take K of them. |
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4) | |
| 7 | {50, 287, 621, 266, 224, 68, 636} | {797, 661, 644, 102, 114, 452, 420} | 2 |
| Returns: 1772 | |
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