TopCoder problem "Rounder" used in SRM 195 (Division II Level One)



Problem Statement

    

Most of the time when rounding a given number, it is customary to round to some multiple of a power of 10. However, there is no reason why we cannot use another multiple to do our rounding to. For example, you could round to the nearest multiple of 7, or the nearest multiple of 3.

Given an int n and an int b, round n to the nearest value which is a multiple of b. If n is exactly halfway between two multiples of b, return the larger value.

 

Definition

    
Class:Rounder
Method:round
Parameters:int, int
Returns:int
Method signature:int round(int n, int b)
(be sure your method is public)
    
 

Constraints

-n will be between 1 and 1000000, inclusive.
-b will be between 2 and 500, inclusive.
 

Examples

0)
    
5
10
Returns: 10
This is a standard rounding base. We round up because 5 is an equal distance between 0 and 10.
1)
    
4
10
Returns: 0
2)
    
100
3
Returns: 99
100 is closer to 99 than 102.
3)
    
123456
7
Returns: 123459
4)
    
49
7
Returns: 49

Problem url:

http://www.topcoder.com/stat?c=problem_statement&pm=2016

Problem stats url:

http://www.topcoder.com/tc?module=ProblemDetail&rd=5070&pm=2016

Writer:

schveiguy

Testers:

lbackstrom , brett1479

Problem categories:

Math